Sum, Count, and Reverse of Digits in Python (While Loop & Recursion)

1. Sum of digits Iterative Approach (Using While Loop) no = int(input("Enter No: ")) sum = 0 while no > 0: sum = sum + no % 10 no = no // 10 else: print(sum) Recursive Approach def sum_of_digits(no): if no == 0: # Base condition return 0 return (no % 10) + sum_of_digits(no // 10) no = int(input("Enter No: ")) result = sum_of_digits(no) print(result) Output 2. Count of digits Iterative Approach (Using While Loop) num = int(input("Enter number: ")) count = 0 while num > 0: num = num // 10 count += 1 print("Count =", count) Recursive Approach def count_digits(num): if num == 0: # base condition return 0 return 1 + count_digits(num // 10) num = int(input("Enter number: ")) # handle edge case when input is 0 if num == 0: print("Count = 1") else: print("Count =", count_digits(num)) Output 3. Reverse a Number Iterative Approach (Using While Loop) num = int(input("Enter number: ")) rev = 0 while num > 0: rev = rev * 10 + num % 10 num = num // 10 print("Reverse =", rev) Recursive Appro